What he’s done is to hard-wire the D0 to D7 inputs to the 0 and 1 values corresponding to the Q output from our original truth table as illustrated below: Now, take a moment to refer back to my chum’s implementation. Basically, we can use our 8:1 multiplexer to implement any 3-input logical function. All we have to do is wire the D0 to D7 inputs to the 0s and 1s we wish to appear on the Q output as illustrated by the desired truth table. The only problem, as I mentioned before, is that my chum made a small error. ![]() Before we proceed further, you may want to take a moment to reflect on the stuff we’ve looked at thus far to see of you can spot the problem.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |